According to NEC regulations, a 12' run of 2-1/2 inch FMC with a total area of 4.909 in² can have what maximum area occupied by circuit conductors?

The correct answer is derived from the guidelines provided in the National Electrical Code (NEC) regarding the maximum allowable fill for conduits. For Flexible Metal Conduit (FMC), the NEC specifies that the fill capacity for conductors must not exceed a certain percentage of the internal cross-sectional area of the conduit.

In the case of a 2-1/2 inch FMC, the total area of 4.909 square inches indicates how much space is available inside the conduit. The Code generally permits a maximum fill of 40% for conductors that are not larger than a specific gauge, and this is the calculation used to determine the maximum area occupied by circuit conductors.

When calculating 40% of 4.909 square inches, the resulting area is approximately 1.963 square inches. This calculation confirms that the maximum area that can be occupied by the circuit conductors inside a 12-foot run of 2-1/2 inch FMC is indeed close to this value. Thus, the result aligns perfectly with the option indicating 1.963 square inches, making it the best choice in this scenario.

In summary, understanding the fill percentage mandates and performing the appropriate calculations based on the conduit size and area are crucial to determining